a.) In families of 4 offspring, what is the probability of finding the oldest and youngest offspring to both be female?
(As you calculate your response, keep variable rounded at 4 decimal places, provide your answer as a percentage with 2 decimal places, no percentage sign needed(%) i.e., 45.21)
b.) Chestnut, Palomino, and Cremello coat coloring is horses is determined by a partial or incomplete dominant mode of inheritance. Chestnut (CC) and cremello (CCrCCr)
animals have a homozygous genotype, and palomino coat coloring is a result from a heterozygous genotype (CCCr)
Two palomino horses have created 3 offspring. What is the chance
that these 3 offspring result in 1 of each color (1 chestnut, 1
cremello, and 1 palomino) colts?
(As you calculate your response, keep variable rounded at 4
decimal places, provide your answer as a percentage with 2 decimal
places, no percentage sign needed(%)i.e., 45.21)
a) The total number of possibilities for the 4 offsprings to be either male or female is
= 2 * 2 * 2 * 2 = 16
The total number of cases in which the youngest and the oldest offspring is female is
= 1 * 2 * 2 * 1 = 4
The probability of finding the oldest and the youngest offsprings to both be female is
= 4/16 = 1/4
The required percentage is = 1/4 * 100 = 25 (answer)
b) The genotype of a Palomino horse is .
The 4 possible genotypes for the offsprings of two Palomino horses are
i) - Chestnut
ii) - Palomino
iii) - Palomino
iv) - Cremello
The probability that an offspring will be Chesnut is = 1/4
The probability that an offspring will be Palomino is = 2/4
The probability that an offspring will be Cremello is = 1/4
The probability that the 3 offsprings result in 1 of each color is
The required percentage is = 18.75
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