The following data were obtained from an independent-measures research study comparing three treatment conditions.
I |
II |
III |
||
n = 6 |
n = 4 |
n = 4 |
||
M = 2 |
M = 2.5 |
M = 5 |
N = 14 |
|
T = 12 |
T = 10 |
T = 20 |
G = 42 |
|
SS = 14 |
SS = 9 |
SS = 10 |
ΣX2tot = 182 |
Use an ANOVA with α = .05 to determine whether there are any
significant mean differences among the treatments.
The null hypothesis in words is
There are no significant differences among the three treatment means.
The alternative hypothesis in symbols is
In ANOVA, we do not state the alternative hypothesis in symbols
Number of treatment, k = 3
Total sample Size, N = 14
df(between) = k-1 = 2
df(within) = N-k = 11
df(total) = N-1 = 13
SS(between) = (T1)²/n1 + (T2)²/n2 + (T3)²/n3 - (Grand Sum)²/ N = 23
SS(within) = SS1 + SS2 + SS3 = 33
SS(total) = SS(between) + SS(within) = 56
MS(between) = SS(between)/df(between) = 11.5
MS(within) = SS(within)/df(within) = 3
F = MS(between)/MS(within) = 3.8333
Critical value Fc = F.INV.RT(0.05, 2, 11) = 3.982
The F-statistic = 3.833
Your decision is
Fail to reject the null hypothesis and conclude that there are not significant differences among the conditions.
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