Question

Michael Jordan made 49.7% of all of his field goals in his career. If one sample of 30 field goals is chosen randomly, what is the probability that he makes over 60%?

Answer 1

Solution :

Given that ,

p = 0.497

1 - p = 0.503

n = 30

= p = 0.497  

= (p*(1-p))/n =  (0.487*0.503)/30 = 0.09129

a.

P( > 0.60) = 1 - P( < 0.60)

= 1 - P(( - ) / < (0.60-0.497) /0.09129)

= 1 - P(z < 1.13)

= 1 - 0.8708

= 0.1292

Probability = 0.1292