Question

In a recent poll, 560 people were asked if they liked dogs, and 66% said they did. Find the margin of error of this poll, at the 99% confidence level.

Answer #1

Solution :

Given that,

n = 560

Point estimate = sample proportion = =66%=0.66

1 - = 1- 0.66 =0.34

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576 ( Using z table )

Margin of error = E = Z / 2 * (((( * (1 - )) / n)

= 2.576* (((0.66*0.34) /560 )

E = 0.052

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[,]

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