In a recent poll, 560 people were asked if they liked dogs, and 66% said they did. Find the margin of error of this poll, at the 99% confidence level.
Solution :
Given that,
n = 560
Point estimate = sample proportion = =66%=0.66
1 - = 1- 0.66 =0.34
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z / 2 * (((( * (1 - )) / n)
= 2.576* (((0.66*0.34) /560 )
E = 0.052
Get Answers For Free
Most questions answered within 1 hours.