given a standard normal distribution, find
A.) the area to the right of z=.83
B.) the area between z1=-.45 and z2=1.22
C.) the value k such that P(Z>k)=.6293
D.) The value z such that the area to the right of z is .3632
a.
b.
c.
Hence
Hence k=-0.1293 such that P(z>-0.1293)=0.6293
d.
So
Hence
Using z table we get z=0.1368 such that
Which means P(z>0.35)=0.3632
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