Question

ou might think that if you looked at the first digit in randomly selected numbers that...

ou might think that if you looked at the first digit in randomly selected numbers that the distribution would be uniform. Actually, it is not! Simon Newcomb and later Frank Benford both discovered that the digits occur according to the following distribution: (digit, probability)

(1,0.301),(2,0.176),(3,0.125),(4,0.097),(5,0.079),(6,0.067),(7,0.058),(8,0.051),(9,0.046)(1,0.301),(2,0.176),(3,0.125),(4,0.097),(5,0.079),(6,0.067),(7,0.058),(8,0.051),(9,0.046)



The IRS currently uses Benford's Law to detect fraudulent tax data. Suppose you work for the IRS and are investigating an individual suspected of embezzling. The first digit of 166 checks to a supposed company are as follows:

Digit Observed
Frequency
1 40
2 20
3 14
4 17
5 19
6 14
7 8
8 17
9 17


a. State the appropriate null and alternative hypotheses for this test.
b. Explain why ?=0.01?=0.01 is an appropriate choice for the level of significance in this situation.
c. What is the P-Value? Report answer to 4 decimal places.
d. What is your decision?
Write a statement to the law enforcement officials that will use it to decide whether to pursue the case further or not. Structure your essay as follows: Given a brief explanation of what a Goodness of Fit test is. Explain why a Goodness of Fit test should be applied in this situation. State the hypotheses for this situation Interpret the answer to part c Use the answer to part c to justify the decision in part d Use the decision in part d to make a conclusion about whether the individual is likely to have embezzled. Use this to then tell the law enforcement officials whether they should pursue the case or not.

Homework Answers

Answer #1

c)

Oi Ei (Oi-Ei)^2/Ei
0.301 40 47.257 1.114417949
0.176 20 27.632 2.10796989
0.125 14 19.625 1.612261146
0.097 17 15.229 0.205951868
0.079 19 12.403 3.508861485
0.067 14 10.519 1.1519499
0.058 8 9.106 0.134332967
0.051 17 8.007 10.10041826
0.046 17 7.222 13.2386159
1 166 157 33.17477936

df= n-1= 9-1 = 8

p-value =

=1 - CHISQ.DIST(36.142506,8,1)

= 0.00001

d)

since p-value < 0.05

we reject the null hypothesis

we conclude that the individual is likely to have embezzled.

the law enforcement officials should pursue the case

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