Consider a small ferry that can accommodate cars and buses. The toll for cars is $3, and the toll for buses is $10. Let X and Y denote the number of cars and buses, respectively, carried on a single trip. Suppose the joint distribution of X and Y is as given in the table below.
y | ||||
p(x,y) | 0 | 1 | 2 | |
x | 0 | 0.025 | 0.015 | 0.010 |
1 | 0.050 | 0.030 | 0.020 | |
2 | 0.105 | 0.075 | 0.050 | |
3 | 0.150 | 0.090 | 0.060 | |
4 | 0.100 | 0.060 | 0.040 | |
5 | 0.050 | 0.030 | 0.040 |
Compute the expected revenue from a single trip. (Round your
answer to two decimal places.)
$
y | |||||
p(x,y) | 0 | 1 | 2 | total=P(X) | |
x | 0 | 0.025 | 0.015 | 0.01 | 0.05 |
1 | 0.05 | 0.03 | 0.02 | 0.1 | |
2 | 0.105 | 0.075 | 0.05 | 0.23 | |
3 | 0.15 | 0.09 | 0.06 | 0.3 | |
4 | 0.1 | 0.06 | 0.04 | 0.2 | |
5 | 0.05 | 0.03 | 0.04 | 0.12 | |
total=P(Y) | 0.48 | 0.3 | 0.22 | 1 |
X | P(X) | X*P(X) |
0 | 0.050 | 0.000 |
1 | 0.100 | 0.100 |
2 | 0.230 | 0.460 |
3 | 0.300 | 0.900 |
4 | 0.200 | 0.800 |
5 | 0.120 | 0.600 |
mean = E[X] = Σx*P(X) = 2.86
=========================
Y | P(Y) | Y*P(y) |
0 | 0.480 | 0.000 |
1 | 0.300 | 0.300 |
2 | 0.220 | 0.440 |
mean = E[Y] = Σy*P(Y) = 0.74
===================
expected revenue from a single trip = $3*E(X) + $10*E(Y) = 3*2.86+10*0.74= $15.98(answer)
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