Activities Probability
0 0.058
1 0.124
2 0.164
3 0.177
4 0.213
5 0.129
6 0.083
7 0.052
Use the probability distribution to complete parts (a) and (b) (c) above.
The number of school-related extracurricular activities per student
Find the (a)mean, (b)variance, and (c)standard deviation of the probability distribution.
Solution :
x | P(x) | x * P(x) | x2 * P(x) |
0 | 0.058 | 0 | 0 |
1 | 0.124 | 0.124 | 0.124 |
2 | 0.164 | 0.328 | 0.656 |
3 | 0.177 | 0.531 | 1.593 |
4 | 0.213 | 0.852 | 3.408 |
5 | 0.129 | 0.645 | 3.225 |
6 | 0.083 | 0.498 | 2.988 |
7 | 0.052 | 0.364 | 2.548 |
(a)
Mean = = X * P(X) = 0.364
(b)
Variance = 2
= X 2 * P(X) - 2
= 2.548 - 0.3642
= 3.373036
(c)
standard deviation
= variance
= 3.373036
= 1.836583
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