Question

Activities   Probability 0   0.058 1   0.124 2   0.164 3   0.177 4   0.213 5   0.129 6   0.083...

Activities   Probability
0   0.058
1   0.124
2   0.164
3   0.177
4   0.213
5   0.129
6   0.083
7   0.052

Use the probability distribution to complete parts​ (a) and​ (b) (c) above.

The number of​ school-related extracurricular activities per student

Find the​ (a)mean, (b)variance, and (c)standard deviation of the probability distribution.

Homework Answers

Answer #1

Solution :

x P(x) x * P(x) x2 * P(x)
0 0.058 0 0
1 0.124 0.124 0.124
2 0.164 0.328 0.656
3 0.177 0.531 1.593
4 0.213 0.852 3.408
5 0.129 0.645 3.225
6 0.083 0.498 2.988
7 0.052 0.364 2.548

(a)

Mean = = X * P(X) = 0.364

(b)

Variance = 2

= X 2 * P(X) - 2

= 2.548 - 0.3642

= 3.373036

(c)

standard deviation

= variance

= 3.373036

= 1.836583

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