Question

An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3 varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in bushels per acre. Treating this as a randomized block design, the results are presented in the table that follows. Fields Smith Walsh Trevor 1 11.1 19.0 14.6 2 13.5 18.0 15.7 3 15.3 19.8 16.8 4 14.6 19.6 16.7 5 9.8 16.6 15.2 86) Referring to Scenario 11-6, the null hypothesis for the randomized block F test for the difference in the means is 86) A) H0: μField1 = μField2 = μField3 = μField4 = μField5 B) H0: μSmith = μWalsh = μTrevor C) H0: MSmith = MWalsh = MTrevor D) H0: MField1 = MField2 = MField3 = MField4 = MField5 87) Referring to Scenario 11-6, what is the null hypothesis for testing the block effects? 87) A) H0: MSmith = MWalsh = MTrevor B) H0: MField1 = MField2 = MField3 = MField4 = MField5 C) H0: μSmith = μWalsh = μTrevor D) H0: μField1 = μField2 = μField3 = μField4 = μField5

Answer 1

(86) null hypothesis for the randomized block F test for the difference in means will include the mean for smith, walsh and Trevor

Null hypothesis will assume that there is no difference in means

This means that the means for all 3 groups will be equal in null hypothesis

So, we can write

therefore, option B is correct

(87) there are five blocks or field, so we will compare the means for each of these five blocks in order to test for the block condition using the null hypothesis

So, for null hypothesis, we will assume that there is no difference in blocks mean for 5 blocks or means are equal for 5 blocks

so, we can write null hypothesis as

option D