The diameters of ball bearings are distributed normally. The mean diameter is 120 millimeters and the standard deviation is 4 millimeters. Find the probability that the diameter of a selected bearing is greater than 125 millimeters. Round your answer to four decimal places.
µ = 120
σ = 4
P ( X > 125 ) = P( (X-µ)/σ ≥ (125-120) /
4)
= P(Z > 1.25 ) = P( Z <
-1.250 ) = 0.1056
(answer)
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