Solution :
Given that,
mean = = 280
standard deviation = = 20
n = 50
= 280
= / n = 20 / 50=2.828
P( <270 ) = P[( - ) / < (270-280) /2.828 ]
= P(z < -3.54)
Using z table
= 0.0002
probability= 0.0002
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