Use the following information to answer questions 9-15.
The length of time spent in the examination room is recorded for each patient seen by each physician at an orthopedic clinic.
Does the data provide a significance difference in mean times?
Physician 1 |
Physician 2 |
Physician 3 |
Physician 4 |
|
34 |
33 |
17 |
28 |
|
25 |
35 |
30 |
33 |
|
27 |
31 |
30 |
31 |
|
31 |
31 |
26 |
27 |
|
26 |
42 |
32 |
32 |
|
34 |
33 |
28 |
33 |
|
21 |
26 |
40 |
||
29 |
||||
X.1=198 |
X. 2=205 |
X.3=218 |
X.4=224 |
The null hypothesis for this ANOVA problem is:
H0: μ1=μ2 |
||
H0: μ1=μ2=μ3
|
||
H0: μ1=μ2=μ3=μ4 |
||
H0: μ1=μ2=μ3=μ4=μ5 |
10 points
QUESTION 10
The total sum of squares, (SST) equals:
450.55 |
||
698.11 |
||
212.35
|
||
485.76 |
10 points
QUESTION 11
The sum of squares between treatments (SSTR) equals:
450.55
|
||
698.11
|
||
212.35 |
||
d) 485.76 |
10 points
QUESTION 12
The test statistic to test the null hypothesis equals:
0.59 |
||
1.06 |
||
3.50 |
||
19.231 |
10 points
QUESTION 13
The null hypothesis is to be tested at the 5% level of significance. The critical value from the table is:
2.54 |
||
3.72
|
||
3.01 |
||
2.78 |
The statistical software output for this problem is :
H0: μ1=μ2=μ3=μ4
SST = 698.11
SSTR = 212.35
test statistic = 3.50
Critical value = 3.01
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