For a population being studied, the null hypothesis for the population mean is H subscript 0 colon mu equals 40 and an alternative hypothesis is H subscript 1 colon mu greater than 40. If a sample of size n equals 26 is randomly selected from the population and the sample mean is calculated to be x with bar on top equals 42.3 with standard deviation s equals 5.6, give the P-value for the right-tailed hypothesis test of mean.
Solution :
= 40
= 42.3
S = 5.6
n = 26
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : = 40
Ha : > 40
Test statistic = t
= ( - ) / S / n
= ( 42.3-40) / 5.6 / 26
= 2.094
Test statistic = t = 2.094
P-value =0.0233
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