Given,
mean = 610, Standard deviation = 20
a.Individual SAT score is less then 600 i.e., p(x<600)
p(z<-0.5) = 1 - p(z>0.5) =1 -0.6915 ..by using Statistical Table
=0.3085
b.Individual SAT score between 590 to 620.
p(-1 < z < 0.5) = 1 - p(z>1) - p(z>0.5)
= 1- 0.15866 -0.30854 ...by using statistical table
=0.5328
c.Individual SAT score is greater than 650.
then p(z>2) = 0.02275 ... by using statistical table
d.Top 5% students score
p(Z>z)=0.05
p(1.64>z)=0.05 ...by using statistical table
Hence, Top 5% students score is 642.89
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