Question

A survey organization takes a simple random sample of  200 households from a city of 50,000 households....

A survey organization takes a simple random sample of  200 households from a city of 50,000 households. On the average there are  2.3 persons per sample household, and the SD is 1.8.

a)  Find a 90%-confidence interval for the average household size in  the city

b)  Find a 80%-confidence interval for the average household size in the city.

c)  If the researcher decreased the sample size to only 50 people, the length of the  80% confidence interval would be:

(i) multiplied by 2        (ii)multiplied by 4         (iii) divided by 2         (iv) divided by 4

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2. A survey organization takes a simple random sample of 200 households from a city of...
2. A survey organization takes a simple random sample of 200 households from a city of 50,000 households. On the average there are 2.3 persons per sample household, and the SD is 1.8. a) Find a 90%-confidence interval for the average household size in the city b) Find a 80%-confidence interval for the average household size in the city. c) If the researcher decreased the sample size to only 50 people, the length of the 80% confidence interval would be:...
A survey is conducted to estimate the average household income in a large metropolitan area. A...
A survey is conducted to estimate the average household income in a large metropolitan area. A random sample of 150 households in this area yielded an average household income of $55,000 with a standard deviation of $13,200. (a) Construct a 95% confidence interval for the mean household income in this area. (Choose the BEST answer) (b) All other information remaining unchanged, which of the following would produce a wider interval than the 95% confidence interval constructed above from Problem (a)?...
A recent survey of 200 households showed that 8 had a single male as the head...
A recent survey of 200 households showed that 8 had a single male as the head of household. Fortyyears ago, a survey of 200 households showed that 6 had a single male as the head of household. Canit be concluded that the proportion has changed? Find the 95% confidence interval of the differenceof the two proportions. Does the confidence interval contain zero? Why is this important to know? For all confidence intervals, include a. difference between sample estimates b. standard...
In a survey of a random sample of 25 households in the Cherry Creek neighborhood of...
In a survey of a random sample of 25 households in the Cherry Creek neighborhood of Denver, it was found that 9 households turned out the lights and pretended not to be home on Halloween. a) Let p be the proportion of all households in Cherry Creek that pretend not to be home on Halloween. Find, a point estimate for p. b) Compute a 85% confidence interval for p. What does a 85% confidence interval mean? c) Check the assumptions...
an agricultural researcher takes a simple random sample of 400 English carrot farms. for the sample...
an agricultural researcher takes a simple random sample of 400 English carrot farms. for the sample she finds that 120 of the farms require irrigation in two of the farms have over 100 acres. which of the following is an approximate 99% confidence interval for the percentage of farms that require irrigation? a. 24% to 36% b. 25% to 35% c. 26% to 34% d. a 99% confidence interval is not possible only 90% and 95% confidence intervals are possible...
A random sample of 30 households was selected from a particularneighborhood. The number of cars for...
A random sample of 30 households was selected from a particularneighborhood. The number of cars for each household is shown below. Estimate the mean number of cars per household for the population of the households in this neighborhood. Give the 95% confidence interval. 2 0 1 2 3 2 1 0 1 4 1 3 2 0 1 1 2 3 1 2 1 0 2 3 0 2 2 1 0 2
A random sample of 45 households was selected as part of a study on electricity usage.,...
A random sample of 45 households was selected as part of a study on electricity usage., and the number of kilowatt-hours (kWh) was recoded for each household. The average usage was found to be 375 kWh. The population standard deviation is given as 51 KWh Assuming the usage is normally distributed, find the margin of error for a 99% confidence interval for the mean. [3 marks] 12.5 14.9 19.6 22.8
A random sample of construction workers was taken in a large city. Of the 125 workers...
A random sample of construction workers was taken in a large city. Of the 125 workers sampled, 21 were unemployed. We wish to construct a 99% confidence interval for the proportion of unemployed construction workers in this city. Assume all assumptions and conditions are met. Part 1 - find the sample proportion part 2 What critical value would you use to be 99% confident? Part 3 Use the appropriate formula to build the confidence interval. Part 4 If we wanted...
2. A research takes a simple random sample of 400 students out of 10,000 students at...
2. A research takes a simple random sample of 400 students out of 10,000 students at a university. On the average, there are .48 cats per sample student, and the SD is .15. Say where each of the following statement is true or false, explain. a. The .48 is .15 or so off the average number of cats per student in the university. b. A 95% confidence interval for the average number of cats per student in the sample is...
2. A research takes a simple random sample of 400 students out of 10,000 students at...
2. A research takes a simple random sample of 400 students out of 10,000 students at a university. On the average, there are .48 cats per sample student, and the SD is .15. Say where each of the following statement is true or false, explain. a. The .48 is .15 or so off the average number of cats per student in the university. b. A 95% confidence interval for the average number of cats per student in the sample is...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT