Question

Assume a significance level of alpha equals 0.05α=0.05 and use the given information to complete parts (a) and (b) below. Original claim: MoreMore than 5454% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.04040.0404. a. State a conclusion about the null hypothesis. (Reject Upper H 0H0 or fail to reject Upper H 0H0.) Choose the correct answer below. A. Fail to rejectFail to reject Upper H 0H0 because the P-value is greater thangreater than alphaα. B. Fail to rejectFail to reject Upper H 0H0 because the P-value is less than or equal toless than or equal to alphaα. C. RejectReject Upper H 0H0 because the P-value is less than or equal toless than or equal to alphaα. D. RejectReject Upper H 0H0 because the P-value is greater thangreater than alphaα. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There isis sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is moremore than 5454%. B. The percentage of adults that would erase all of their personal information online if they could is lessless than or equal to 5454%. C. There is notis not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is moremore than 5454%. D. The percentage of adults that would erase all of their personal information online if they could is moremore than 5454%. Click to select your answer.

Answer #1

given that the p value is 0.04, which is less than the significance level of 0.05

this means that the result is significant and we can reject the null hypothesis

so, we can say that less than 54% of all users erase their data.

(A) option C is correct answer because p value is less than alpha level of 0.05

(B) we know that the claim was that More than 54% of adults would erase all of their personal information online if they could, but we failed to support this data.

So, we can say that less than 54% of adults would erase all of their personal information online if they could,

therefore, option C

Assume a significance level of alpha = 0.05 and use the given
information to complete parts (a) and (b) below. Original claim:
The standard deviation of pulse rates of a certain group of adult
males is more than 11 bpm. The hypothesis test results in a
P-value of 0.2761.
a. State a conclusion about the null hypothesis.
(Reject H0 or fail to reject H0.)
Choose the correct answer below.
A. Fail to reject H0 because the P-value is less
than...

Assume a significance level of alpha equals 0.1 and use the
given information to complete parts (a) and (b) below.
Original claim: The standard deviation of pulse rates of a
certain group of adult males is more than 17 bpm. The hypothesis
test results in a P-value of 0.2678
a. State a conclusion about the null hypothesis. (Reject Upper
H 0 or fail to reject Upper H 0.) Choose the correct answer
below.
A. Reject Upper H 0 because the...

Assume a significance level of α=0.1 and use the given
information to complete parts (a) and (b) below.
Original claim: Women have heights with a mean equal to 156cm.
The hypothesis test results in a P-value of 0.0676
a. State a conclusion about the null hypothesis. (Reject H0 or
fail to reject H0.) Choose the correct answer below.
A. Fail to reject H0 because the P-value is greater than
alphaα.
B. Reject H0 because the P-value is greater than alphaα....

In the following exercise, use a significance level of α = 0.05
to
State a conclusion about the null hypothesis. (Reject
H0 or fail to reject H0 )
Without using technical terms or symbols, state a conclusion
that addresses the original claim.
Original Claim: More than 58% of adults would erase all their
personal information online if they could. The hypothesis test
results in a P-value of 0.3257.

A poll of
2 comma 1172,117
randomly selected adults showed that
9191%
of them own cell phones. The technology display below results
from a test of the claim that
9393%
of adults own cell phones. Use the normal distribution as an
approximation to the binomial distribution, and assume a
0.010.01
significance level to complete parts (a) through (e).
Test of
pequals=0.930.93
vs
pnot equals≠0.930.93
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
19241924
2 comma 1172,117
0.9088330.908833
(0.8927190.892719,0.9249480.924948)...

Assume a significance level of alpha equals 0.1 and use the
given information to complete parts (a) and (b) below. Original
claim: The mean pulse rate (in beats per minute) of a certain
group of adult males is 68 bpm. The hypothesis test results in a
P-value of 0.0661.
a. State a conclusion about the null hypothesis. (Reject H 0 or
fail to reject H 0.) Choose the correct answer
below.
b. Without using technical terms, state a final conclusion that...

In a recent court case it was found that during a period of 11
years 893 people were selected for grand jury duty and 38% of them
were from the same ethnicity. Among the people eligible for grand
jury duty, 78.9% were of this ethnicity. Use a 0.01 significance
level to test the claim that the selection process is biased
against allowing this ethnicity to sit on the grand jury. Identify
the null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion...

The dean of a university estimates that the mean number of
classroom hours per week for full-time faculty is
11.011.0.
As a member of the student council, you want to test this
claim. A random sample of the number of classroom hours for eight
full-time faculty for one week is shown in the table below. At
alphaαequals=0.100.10,
can you reject the dean's claim? Complete parts (a) through
(d) below. Assume the population is normally distributed.
10.810.8
9.49.4
12.712.7
6.16.1
4.94.9...

Assume that the significance level is alpha equals α=0.05.
Use the given information to find the P-value and the critical
value(s).
With
Upper H 1 : p not equals 1/2,
the test statistic is
zequals=negative −1.77.

Assume that the significance level is alpha equals 0.05. Use the
given information to find the? P-value and the critical? value(s).
The test statistic of z = -1.07 is obtained when testing the claim
that p greater than 0.4.

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