Question

Estimate the minimum sample size needed to achieve the margin of error E equals = 0.293

Answer #1

Solution :

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z_{/2}
= Z_{0.025} = 1.96

sample size = n = (Z_{ / 2} / E )^{2} *
* (1 - )

= (1.96 / 0.293)^{2} * 0.5 * 0.5

= 11.18 = 12

Minimum sample size = 12

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(a)
203
(b)
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(c)
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α =
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1 − α/2 =
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Group of answer choices
163
13
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