Assume that a sample is used to estimate a population mean μ . Find the 99.5% confidence interval for a sample of size 279 with a mean of 56.9 and a standard deviation of 11.5. Enter your answer as a tri-linear inequality accurate to 3 decimal places. < μ
The 99.5% confidence interval is:
Explanation:
Mean = 56.9
Sd = 11.5
Sample size n = 279
Since the sample size is large it is good to assume sample sd as population sd
Significance level = 1 -99.5/100 = 0.005
Formula to calculate the confidence interval:
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