Question

17)Draw the standard normal distribution. Shade the area to the between of -2.68 and 1.49. Find the shaded area.

18)Draw the standard normal distribution. Shade the area to the left of the z-score is 0.907. Find the z-score.

Answer #1

Solution:

Shade area

= P( between of -2.68 and 1.49)

= P[-2.68 < Z < 1.49]

= P(Z < 1.49) - P(Z < -2.68)

= 0.9319 - 0.0037

= 0.9282

**Answer : shaded area. = 0.9282**

18)

Given that , P(Z < z score ) = 0.907

Use z table , see where is probability 0.907 and then see the corresponding z value .

So , P(z < 1.32) = 0.907 approximately

So , required z score is 1.32

**required z score is 1.32**

Find the area under the standard normal curve below. Draw a
graph and shade the area you are trying to find to the left of z =
1.85.

Assume a standard Normal distribution. Draw a well-labeled
Normal curve for each part.
a. Find the z-score that gives a left area of 0.7303
b. Find the z-score that gives a left area of 0.1647

Find the following probabilities.
Draw a picture of the normal curve and shade the area :
1. P (z ≤ 1.31) =
2. P (z ≥ 1.65) =
3. P (−2.17 ≤ z ≤ 2.18) =

Use the given shaded area (0.2549) in the middle of the
standard normal distribution and the given z-score (-1.14) to find
the missing z-score. The shaded region is not symmetric about
z
=
0
z
=
0
. Round your final answer to two decimal places.
-4
-3
-2
-1
0
1
2
3
4
z
Shaded Area = 0.2549
-1.14
?
Upper z-score =

Find the area of the shaded region. The graph depicts the
standard normal distribution of bone density scores with mean 0 and
standard deviation 1. font size decreased by 2 z equals negative
0.93 font size decreased by 2 z equals 1.28 A symmetric bell-shaped
curve is plotted over a horizontal scale. Two vertical lines run
from the scale to the curve at labeled coordinates “z equals
negative 0.93,” which is to the left of the curve’s center and
peak,...

In Exercises 16 and 17, find the indicated area under the curve
of the standard normal distribution, then convert it to a
percentage and fill in the blank.
16. About _______% of the area is between z = -0.75 and z = 0.75
(or within 0.75 standard deviations of the mean).
17. About _______% of the area is between z = -1.5 and z = 1.5
(or within 1.5 standard deviations of the mean).

Find the area of the shaded region. The graph depicts the
standard normal distribution of bone density scores with mean 0 and
standard deviation 1. z=0.81 and z=1.23

Find the area under the standard normal distribution curve for
each of the following. (
a.) Between z = 0 and z = -2.34
b.) To the right of z = -2.11
c.) To the left of z = 1.31
d.) To the left of z = - 1.45
e.) To the right of z = - .85

Find the area of the shaded region. the graph depicts
the standard normal distribution bone density scores that are
normally distributed with a mean of 0 and a standard deviation of
1. z= - "89 ," z= 1.22

Q1-. A normal distribution has a mean of 15 and a standard
deviation of 2. Find the value that corresponds to the 75th
percentile. Round your answer to two decimal places.
Q2-.Tyrell's SAT math score was in the 64th percentile. If all
SAT math scores are normally distributed with a mean of 500 and a
standard deviation of 100, what is Tyrell's math score? Round your
answer to the nearest whole number.
Q3-.Find the z-score that cuts off an area...

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