17)Draw the standard normal distribution. Shade the area to the between of -2.68 and 1.49. Find the shaded area.
18)Draw the standard normal distribution. Shade the area to the left of the z-score is 0.907. Find the z-score.
= P( between of -2.68 and 1.49)
= P[-2.68 < Z < 1.49]
= P(Z < 1.49) - P(Z < -2.68)
= 0.9319 - 0.0037
Answer : shaded area. = 0.9282
Given that , P(Z < z score ) = 0.907
Use z table , see where is probability 0.907 and then see the corresponding z value .
So , P(z < 1.32) = 0.907 approximately
So , required z score is 1.32
required z score is 1.32
Get Answers For Free
Most questions answered within 1 hours.