Find the following probabilities for the standard normal random variable z. (Round your answers to four decimal places.)
(a) P(−1.43 < z < 0.64) =
(b) P(0.52 < z < 1.75) =
(c) P(−1.56 < z < −0.48) =
(d) P(z > 1.39) =
(e) P(z < −4.34) =
Solution:
a) To find P ( -1.43 < z < 0.64)
= P( z < 0.64 ) - P( z < -1.43)
= 0.7389 - 0.0764. From Z table
= 0.6625
P( -1.43 < z < 0.64 ) = 0.6625
b) To find P( 0.52 < z < 1.75)
= P( z < 1.75 ) - P( z < 0.52)
= 0.9599 - 0.6985. From Z table
= 0.2614
P( 0.52 < z < 1.75) = 0.2614
c) To find P( -1.56 < z < -0.48)
= P( z < -0.48) - P( z < -1.56)
= 0.3156 - 0.0594. From Z table
= 0.2562
P( -1.56 < z < -0.48) = 0.2562
d) To find P( z > 1.39)
= P( z > 1.39)
= 0.0823 From Z table
e) To find P( z < -4.34)
= P( z < - 4.34)
=0.0000. From Excel
P( z < -4.34) = 0.0000
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