Using the Poisson distribution function, if 1.1 accidents can be expected at a certain intersection every day, what is approximately the probability that there will be three accidents at that intersection on any given day?
a) 0.048
b) 0.7685
c) 0.0738
d) 0.4212
e) None of the Above
We know Poisson distribution PDF is
Where we have given
1.1 accidents can be expected at a certain intersection every day
m = parameter in Poisson distribution = 1.1
We have given X = 3 because There will be three accidents at that intersection on any given day
Round to 4 decimal place
Final answer :-
Correct choice is (c)
0.0738
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