In a survey, 20 people were asked how much they spent on their
child's last birthday gift. The results were roughly bell-shaped
with a mean of $46 and standard deviation of $13. Construct a
confidence interval at a 90% confidence level.
Give your answers to one decimal place.
Solution :
Given that,
t /2,df = 1.729
Margin of error = E = t/2,df * (s /n)
= 1.729 * (13 / 20)
Margin of error = E = 5
The 90% confidence interval estimate of the population mean is,
- E < < + E
46 - 5 < < 46 + 5
41 < < 51
(41 , 51)
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