Question

A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. Those 21 participants on the drug had an average test score of 29.077 (SD = 4.199) while those 30 participants not on the drug had an average score of 44.087 (SD = 5.152). You use this information to create a 95% confidence interval for the difference in average test score. What is the margin of error? Assume the population standard deviations are equal. options: 1) 1.36171784 2) 2.00957524 3) 2.669 4) 2.283 5) 2.736

Answer 1

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