So according to question we have to find E(x) .
Probability of winning $500 is 1/200 and not winning is 199/200 .
And E(X)=xip(xxi)
= 500 × (1/200) + (-3)×(199/200)
*[we have taken -3 , as it is mentioned that it is not refunded , so it can be regarded as a loss of $3 indicated by a negative sign ]*
= -0.485
So expected value is a loss of 0.485 $ .
Fair price = cost of playing the game + expected value earned from the game
Fair price of the ticket is = 3-0.485= 2.515 $
It can be done by other way too
Let the price be "x".
The random variable values are 500 and -x
The probabilities are 1/200 and 199/200
Multiplying and add you get:
500(1/200)+x(199/200) = 0
500 + 199x = 0
x = -(500/199) dollars
x = -2.5125 dollars
The price to play should be 2.515$ (approx)
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