By observing the sample space of the die and chips, determine the probability of obtaining:
- the number 3 and the color black
- an even number and the color white
- a number less than 3 and the color white
I am assuming that the chip has two sides : Black and White. So, the sample space for die is {1,2,3,4,5,6} and the sample space of chip is {Black, White}. As the outcome of chip and die are independent, the probability will be multiplied by the law of indepedent events. I am also assuming that the die is unbiased, i.e probability of occurring any number in the sample space is 1/6. The same unbiasedness is true for chip.
a) P(the number 3 and the color black) = P(the number 3) * P( the color black) = 1/6 * 1/2 = 1/12
b) P(an even number and the color white) = P(an even number) * P( the color white) = 3/6 * 1/2 = 1/4
c) P(a number less than 3 and the color white) = P(a number less than 3) * P( the color white) = 2/6 * 1/2 = 1/6
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