The mean life of 20 printers is 1014 hours. Their lifetimes are normally distributed with σ = 25 hours. Which of the following is the smallest number of sample size that assures if we wanted to be 95% confident that the error in estimating the mean life is less than 5 hours?
We want to be 95% confident that the error in estimating the mean life is less than 5 hours.
This is means that are margin of error needs to be less than 5 hours
This if for population mean and we hvae the population SD therefore we will use the normal distribution to calculate the C.V
Margin of error = C.v. * SE
Margin of error =
= 1 - 0.95 = 0.05
C.V. = Z0.025
= 1.96 using normal distribution tables
σ = 25
SE = 25 /
MOE = 1.96 * 25 /
MOE < 5
1.96 * 25 / <5
n > 96.04
n= 96
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