Question

For a confidence level of 85%, find the critical value to 2 decimal places. For a confidence level of 85%, find the critical value to 2 decimal places.

z =

Answer 1

For a confidence level of 85%, the critical value of Z be:-

[ explanation:-

confidence level (c) = 85% = 0.85

= (1-c) = (1-0.85) = 0.15

( in any blank cell of excel type =NORMSINV(0.075) press enter....then take the absolute value)]

*** if you have any doubt regarding the problem please write it in the comment box.if you are satisfied please give me a LIKE if possible...