Question

Air crew escape systems are powered by a solid propellant. The burning rate of this propellant is an important product characteristic. Specifications require that the mean burning rate must be 50 centimeters per second and the standard deviation is s = 2 centimeters per second. The significance level of a = 0.05 and a random sample of n = 25 has a sample average burning rate of centimeters per second. Draw conclusions.

Complete the seven-step procedure

1.Parameter of interest: The parameter of interest is mu, the mean burning rate.

2.Null hypothesis: H0:

3.Alternative hypothesis: H1:

4.Test Statistic:

5.Reject H0 if:

6.Computations:

7.Conclusion:

Answer 1

Given

s = 2

n = 25

1. .Parameter of interest:

  The parameter of interest is , the mean burning rate.

2.Null hypothesis:

  

3.Alternative hypothesis:

4.Test Statistic:

5.Reject H0 if:  

Reject H₀ , if the P-value is less than the significance level.

6.Computations:

n = 25

Degrees of freedom = n -1 = 25 -1 =24

From Quick P Value from T Score Calculator,

putting T score = 3.25

DF = 24

Significance Level = 0.05

Two -tailed

We get,

The p-value =.003402

7.Conclusion:

Since the P-value (.0034) is less than the significance level (0.05), we reject the null hypothesis.