In a statistics class of 38 students, 12 have volunteered for community service in the past. If two students are selected at random from this class, what is the probability that both of them have volunteered for community service? Round your answer to four decimal places. P ( both students have volunteered for community service ) =
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Answer:
Number of ways to select 2 students that have volunteered for community class from the
12 students volunteered for community service by 12C2 ways.
Total number of ways to select 2 students from 38 students by 46C2 ways.
In general nCr = n! / [ (n-r)! * r! ]
Therefore,
P(Both students have volunteered for community service) = 12C2 / 38C2
= 66 / 703
= 0.0938
P ( both students have volunteered for community service ) = 0.0938
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