Unfortunately, arsenic occurs naturally in some ground water†. A mean arsenic level of μ = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 41 tests gave a sample mean of x = 7.0 ppb arsenic, with s = 2.4 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use α = 0.01. (a) What is the level of significance? State the null and alternate hypotheses. H0: μ = 8 ppb; H1: μ < 8 ppb H0: μ = 8 ppb; H1: μ > 8 ppb H0: μ > 8 ppb; H1: μ = 8 ppb H0: μ < 8 ppb; H1: μ = 8 ppb H0: μ = 8 ppb; H1: μ ≠ 8 ppb (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The Student's t, since the sample size is large and σ is known. The Student's t, since the sample size is large and σ is unknown. The standard normal, since the sample size is large and σ is unknown. The standard normal, since the sample size is large and σ is known. What is the value of the sample test statistic? (Round your answer to three decimal places.) (c) Estimate the P-value. P-value > 0.250 0.100 < P-value < 0.250 0.050 < P-value < 0.100 0.010 < P-value < 0.050 P-value < 0.010 Sketch the sampling distribution and show the area corresponding to the P-value. WebAssign Plot WebAssign Plot WebAssign Plot WebAssign Plot (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α? At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. (e) Interpret your conclusion in the context of the application. There is sufficient evidence at the 0.01 level to conclude that the mean level of arsenic in the well is less than 8 ppb. There is insufficient evidence at the 0.01 level to conclude that the mean level of arsenic in the well is less than 8 ppb.
(a) The level of significance is α = 0.01
The null and alternative hypothesis is ,
H0: μ = 8 ppb; H1: μ < 8 ppb
The test is left-tailed test.
(b) The Student's t, since the sample size is large and σ is unknown.
The test statistic is ,
(c) Now , df=degrees of freedom=n-1=41-1=40
The p-value is ,
p-value= ; The Excel function is , =TDIST(2.668,40,1)
From t-table , p-value <0.01
(d) Decision : Here , p-value < 0.01
Therefore , reject Ho.
At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant
(e) There is sufficient evidence at the 0.01 level to conclude that the mean level of arsenic in the well is less than 8 ppb.
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