The scores on the exam public health professionals take to be certified follows a normal distribution with a mean score of 75 points and a standard deviation of 7 points.
What is the probability someone scores 71.5 or more on the exam?
Solution :
Given that ,
mean = = 75
standard deviation = = 7
P(x 71.5) = 1 - P(x 71.5)
= 1 - P[(x - ) / (71.5 - 75) / 7]
= 1 - P(z -0.5)
= 1 - 0.3085
= 0.6915
Probability = 0.6915
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