Question

According to a study, 78% of adults ages 18-29 years had broadband internet access at home...

According to a study, 78% of adults ages 18-29 years had broadband internet access at home in 2011. A researcher wanted to estimate the proportion of undergraduate college students 18-23) with access, so she randomly sample 182 undergraduates and found that 159 had access. Estimate the true proportion with 90% confidence.

Homework Answers

Answer #1

given data and necessary calculation:-

sample size (n) = 159

sample proportion () = 159/182 = 0.8736

z critical value for 90% confidence level, both tailed test be:-

the 90% confidence interval for the true proportion be:-

*** if you have any doubts about the problem please mention it in the comment box... if satisfied please LIKE.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
According to a study, 78% of all ages 18-29 years had broadband internet access at random...
According to a study, 78% of all ages 18-29 years had broadband internet access at random home in 2011. A researcher wanted to estimate the proportion of undergraduates college student (18-23) with access, so she randomly sampled 184 undergraduates and found that 161 had access. Estimate the true proportion with 99%confidence.
In a recent year, a study found that 77% of adults ages 18–29 had internet access...
In a recent year, a study found that 77% of adults ages 18–29 had internet access at home. A researcher wanted to estimate the proportion of undergraduate college students (18–29 years) with access, so she randomly sampled 187 undergraduates and found that 165 had access. Estimate the true proportion with 99% confidence. Round intermediate answers to five decimal places. Round your final answer to one decimal place.
1. According to the Pew Research Center, 73% of adults in the U.S. have broadband access...
1. According to the Pew Research Center, 73% of adults in the U.S. have broadband access in their homes. An internet access advocacy group thinks that rate is different among Saint Paul high school students. A. What are the null and alternative hypotheses for a test on this claim? Is this a one-sided or two-sided test? Is the claim represented by the null or alternative hypothesis? b. A survey of Saint Paul high school students finds that 135 out of...
A survey of adults ages? 18-29 found that 93?% use the Internet. You randomly select 132...
A survey of adults ages? 18-29 found that 93?% use the Internet. You randomly select 132 adults ages? 18-29 and ask them if they use the Internet.? (a) Find the probability that exactly 125 people say they use the Internet.? (b) Find the probability that at least 125 people say they use the Internet.? (c) Find the probability that fewer than 125 people say they use the Internet. ?(d) Are any of the probabilities in parts? (a)-(c) unusual? Explain.
A survey of adults ages​ 18-29 found that 85​% use the Internet. You randomly select 157...
A survey of adults ages​ 18-29 found that 85​% use the Internet. You randomly select 157 adults ages​ 18-29 and ask them if they use the Internet. ​(a) Find the probability that exactly 134 people say they use the Internet. ​(b) Find the probability that at least 134 people say they use the Internet. ​(c) Find the probability that fewer than 134 people say they use the Internet. ​(d) Are any of the probabilities in parts​ (a)-(c) unusual? Explain. Use...
According to a Pew Research Center study, in May 2011, 42% of all American adults had...
According to a Pew Research Center study, in May 2011, 42% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 420 community college students at random and finds that 188 of them have a smart phone. Then in testing the hypotheses: H0: p = 0.42 versus Ha: p > 0.42, what...
According to a Pew Research Center study, in May 2011, 32% of all American adults had...
According to a Pew Research Center study, in May 2011, 32% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 351 community college students at random and finds that 130 of them have a smart phone. In testing the hypotheses: H 0 : p = 0.32 versus H a : p...
According to a Pew Research Center study, in May 2011, 43% of all American adults had...
According to a Pew Research Center study, in May 2011, 43% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 281 community college students at random and finds that 145 of them have a smart phone. Then in testing the hypotheses: H 0 : p = 0.43 versus H a :...
According to a Pew Research Center study, in May 2011, 43% of all American adults had...
According to a Pew Research Center study, in May 2011, 43% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 405 community college students at random and finds that 196 of them have a smart phone. Then in testing the hypotheses: H0: p = 0.43 versus Ha: p > 0.43, what...
According to a Pew Research Center study, in May 2011, 34% of all American adults had...
According to a Pew Research Center study, in May 2011, 34% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 339 community college students at random and finds that 136 of them have a smart phone. In testing the hypotheses: H 0 : p = 0.34 versus H a : p...