According to a study, 78% of adults ages 18-29 years had broadband internet access at home in 2011. A researcher wanted to estimate the proportion of undergraduate college students 18-23) with access, so she randomly sample 182 undergraduates and found that 159 had access. Estimate the true proportion with 90% confidence.
given data and necessary calculation:-
sample size (n) = 159
sample proportion () = 159/182 = 0.8736
z critical value for 90% confidence level, both tailed test be:-
the 90% confidence interval for the true proportion be:-
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