Question

# Use the given information to find the P-value. Also use a 0.05 significance level and state...

Use the given information to find the P-value. Also use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).

(a) The test statistic in a right-tailed test is z = 2.00

(b) The test statistic of z = -1.75 is obtained when testing the claim that p = 1/3

a) Here, we are given the z test statistic as z = 2 and as this is a right tailed test, the p-value here is computed as:

p = P( Z > 2 ) = 0.0228 ( from the standard normal tables )

As the p-value here is 0.0228 < 0.05 which is the level of significance, therefore the test is significant and we can reject the null hypothesis here.

b) For testing the claim p = 1/3, this is a two tailed test, and therefore the p-value here is computed from the standard normal tables as:

p = 2P( Z < -1.75 ) = 2*0.0401 = 0.0802

As the p-value here is 0.0802 > 0.05 which is the level of significance, therefore the test is not significant and we cannot reject the null hypothesis here.

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