Question

A normal population has mean =μ9 and standard deviation =σ5.

(a) What proportion of the population is less than 20?

(b) What is the probability that a randomly chosen value will be greater than 5?

Round the answers to four decimal places.

Answer #1

A) Given data

Mean value(X')=9

Standard deviation (S)=5

a)We need to determine the proportion of population that is less than 20 is

i.e P(X<20)

First determine z score value

Z score=(X-X')/S

=(20-9)/5=2.2

P(X<20)=P(Z<2.2)

=0.9861( From normal area tables)

The proportion of the population is less than 20 =0.9861

b) We need to determine the probability that a randomly choosen Value will be greater than 5 is

i.e P(X>5)

Z score Value=(X-X')/S

=(5-9)/5

=-0.8

P(X>5)=P(Z>-0.8)

=0.7881(From normal area tables)

So,the probability that a randomly selected Value greater than5 is=0.7881

normal population has mean =μ10 and standard deviation =σ7. (a)
What proportion of the population is less than 18? (b) What is the
probability that a randomly chosen value will be greater than 3?
Round the answers to four decimal places. Part 1 of 2 The
proportion of the population less than 18 is . Part 2 of 2 The
probability that a randomly chosen value will be greater than 3 is
.

A normal population has mean μ= 34 and standard deviation σ=
10.
(a) What proportion of the population is between 10 and 20?
(b) What is the probability that a randomly chosen value will be
between 28 and 38?
Round the answers to at least four decimal places

A normal population has mean μ =40 and standard deviation σ
=9.
(a) What proportion of the population is between 20 and 30?
(b) What is the probability that a randomly chosen value will be
between 35 and 45?
Round the answers to at least four decimal places.

A normal population has mean μ=40 and standard deviation σ
=9.
(a) What proportion of the population is between 20 and 30 ?
(b) What is the probability that a randomly chosen value will be
between 35 and 45?
Round the answers to at least four decimal places

A normal population has mean μ = 9 and standard
deviation σ = 6.
a.
What proportion of the population is less than 20?
b.
What is the probability that a randomly chosen value will be
greater than 5?

A normal population has a mean of 61 and a standard deviation of
20. A. What proportion of the population is greater than 108? B.
What is the probability that a randomly chosen valve will be less
than 81?

A normal population has mean μ = 31 and standard deviation σ =
6. (a) What proportion of the population is between 19 and 28? (b)
What is the probability that a randomly chosen value will be
between 26 and 36? Round the answers to at least four decimal
places. Part 1 of 2 The proportion of the population between 19 and
28 is . Part 2 of 2 the probability that a randomly chosen value
will be between 26...

A normal population has mean μ 30 = 31 and standard deviation σ=
7
(a) What proportion of the population is between 15 and 25?
(b) What is the probability that a randomly chosen value will be
between 25 and 35?
Round the answers to at least four decimal places.

A normal population has a mean of 77 and a standard deviation of
5. You select a sample of 48.
Compute the probability that the sample mean is: (Round
your z values to 2 decimal places and final answers to 4
decimal places.)
A. less than 76
Probability:
B. Between 76 and 78
Probability:
C. Between 78 and 79
Probability:
D. Greater than 79
Probability:

A normal population has a mean of 21 and a standard deviation of
5.
a. Compute the Z value associated with 25 (round answer to 2
decimal places)
b. What proportion of the population is between 21 and 25?
(Round z-score computation to 2 decimal places and final answer to
4 decimal places)
c. What proportion of the population is less than 17? (Round
z-score computation to 2 decimal places and final answer to 4
decimal places)

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