2) In a survey of 2223 adults, 1167 think antibiotics are effective against viral infections. Construct a 99% confidence interval for the true population proportion. Round your final answers to the nearest thousandths (3 numbers after the decimal).
We have given here,
x=1167
n=2223
Estimate for sample proportion= 0.525
Level of significance is =1-0.99=0.01
Z critical value(using Z table)=2.576
Lower limit for confidence interval=0.498
Upper limit for confidence interval=0.552
Get Answers For Free
Most questions answered within 1 hours.