The diameters of ball bearings are distributed normally. The mean diameter is 89 millimeters and the variance is 9. Find the probability that the diameter of a selected bearing is between 83 and 91 millimeters. Round your answer to four decimal places.
Solution :
Given that,
mean = = 89
variance = 2= 9
standard deviation = = 3
P (83 < x < 91 )
P ( 83 - 89 / 3) < ( x - / ) < ( 91 - 89 / 3)
P ( - 6 / 3 < z < 3 / 3 )
P (-2 < z < 1 )
P ( z < 1) - P ( z < -2)
Using z table
=0.8413 - 0.0228
= 0.8185
Probability = 0.8185
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