Question

According to a recent survey, 12% of the population is left handed. If you randomly select 6 people what is the probability that at least one of them is left handed?

Round your answer to three decimal places.

Answer 1

Answer)

As there are fixed number of trials and probability of each and every trial is same and independent of each other

Here we need to use the binomial formula

P(r) = ncr*(p^r)*(1-p)^n-r

Ncr = n!/(r!*(n-r)!)

N! = N*n-1*n-2*n-3*n-4*n-5........till 1

For example 5! = 5*4*3*2*1

Special case is 0! = 1

P = probability of single trial = 0.12

N = number of trials = 6

R = desired success = at least 1.

We know that sum of all the probabilities is = 1.

So, P(at least 1) = 1 - P(0).

= 0.535595913216