Find the following:
a. n = 24, area to the right is, .025, t = …….
b. df = 30, confidence level is 94%, t = …….
c.For confidence level 92%, Z= ……..
d. If the area to the right is .005, then Z =…….
Solution:
a)
Using t-distribution table,
t0.025,23 = 2.069
b)
At 94% confidence level the t is ,
= 1 - 94% = 1 - 0.94 = 0.06
/ 2 = 0.06 / 2 = 0.03
t /2,df = t0.03,30 = 1.955
c)
Using standard normal table,
At 92% confidence level the z is ,
= 1 - 92% = 1 - 0.92 = 0.08
/ 2 = 0.08 / 2 = 0.04
Z/2 = Z0.04 = 1.751
d)
P(Z > 0.05 ) = 1 - P(z < 0.05)
= 1 - 0.5199 Using standard normal table.
= 0.4801
Area = 0.4801
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