Find the margin of error.
The lifetimes (in months) of a set of 50 randomly selected automobile batteries of a particular brand gives a mean of 16 months with a standard deviation of 1.5 months. The manufacturer claims, however, that this particular make of battery has an 18 month lifetime.
To find the margin of error we need confidence level .
Which is not given in the question.
Therefore we use 95% confidence level.
As population standard deviation not given we use t-interval formula to get margin of error.
We have given that : n=50 , s=1.5
c=0.95
Degrees of freedom= n-1 = 50-1 =49
DF= 49
To get the value of tc use Excel function
TINV(probability,deg_freedom)
= TINV( 0.05 , 49 )
= 2.009575
tc = 2.01
Now plug the values in the formula
E = 0.4263853891
Margin of error = 0.426 (rounded to three decimals)
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