> x=c(5,3,1,6,4,3,2,4,7)
> y=c(7,4,1,8,5,2,4,7,9)
> mean(x)
[1] 3.888889
> mean(y)
[1] 5.222222
> sd(x)
[1] 1.900292...
> x=c(5,3,1,6,4,3,2,4,7)
> y=c(7,4,1,8,5,2,4,7,9)
> mean(x)
[1] 3.888889
> mean(y)
[1] 5.222222
> sd(x)
[1] 1.900292
> sd(y)
[1] 2.728451
> t.test(x,y,var.equal=T)
Two Sample t-test
data: x and y
t = -1.203, df = 16, p-value = 0.2465
alternative hypothesis: true difference in means is not equal to
0
95 percent confidence interval:
-3.682888 1.016221
sample estimates:
mean of x mean of y
3.888889 5.222222
> t.test(x,y,var.equal=F)
Welch Two Sample t-test
data: x and y
t = -1.203,...
Using SPSS, the outcome of the data analysis are as follow;
Paired Differences
95% Confidence Interval...
Using SPSS, the outcome of the data analysis are as follow;
Paired Differences
95% Confidence Interval of the difference
Mean
Std. Deviation
Std. Error Mean
Lower
Upper
T
df
Sig.(2-tailed)
Pair 1
Method A-Method B
5.200
6.125
1.937
0.819
9.581
2.685
9
1-Provide a statement about the finding in this table for paired
t-test and it is interpretation?
2-Report the estimate difference for ua-ub
between the mean scores obtained by children taught by the two
methods and its 95% confidence...
(7) A new drug is developed to treat headache, and we want to
compare its performance...
(7) A new drug is developed to treat headache, and we want to
compare its performance with an existing drug. The performance
measure here is the time from taking the drug to people start to
feel better. A random sample of volunteers were collected, in one
occasion of headache, these people use one of the drug, and then in
another occasion of headache (there is a long time between
occasions), these volunteers use the other drug. Assuming all
variables are...
Using the table below, would you please check my answers. The
answer for the p-value is...
Using the table below, would you please check my answers. The
answer for the p-value is supposed to be 0.0000; however, I
keep getting 0.9999999977 as the answer. How
do you find the correct p-value? Where am I going wrong in my
calculation?
Regardless of your answer to part (a) using R, run a t-test for
the difference between the two treatment means at the α = 5% level
of significance. Specifically, we are interested in
knowing if there exists...
E. Using the same data, assuming that they are independent
sample and not paired. Using SPSS,...
E. Using the same data, assuming that they are independent
sample and not paired. Using SPSS, the outcome of the data analysis
as follow.
Independent Samples Test
Levene’s Test for equality of variances
t-test for equality of means
95% Confidence Interval of the difference
F
Sig.
t
df
Sig.(2-tailed)
Mean Difference
Std. Error Difference
Lower
Upper
Test score
Equal variances assumed
0.153
0.700
1.215
18
.240
5.200
4.280
-3.793
14.193
Equal variances not assumed
1.215
17.694
.240
5.200
4.280
-3.804...