Population Growth and Value Decline
Mini-projects are designed to critically stretch your thinking, let you explore the concept, or make you look at a specific situation or related problem. By nature, they are more difficult than the regular exercises.
Problem:: The number of Starbucks stores grew after they first opened. The number of stores from 1990-2011, as reported on their corporate website is shown in the chart below..
Carefully plot the data. You should be able to see that the data is NOT linear, but actually exponential.
Year |
Number of Starbucks stores |
Year |
Number of Starbucks stores |
1990 |
84 |
2001 |
4709 |
1991 |
116 |
2002 |
5886 |
1992 |
165 |
2003 |
7225 |
1993 |
272 |
2004 |
8569 |
1994 |
425 |
2005 |
10241 |
1995 |
677 |
2006 |
12440 |
1996 |
1015 |
2007 |
15011 |
1997 |
1412 |
2008 |
16680 |
1998 |
1886 |
2009 |
16635 |
1999 |
2498 |
2010 |
16858 |
2000 |
3501 |
2011 |
17003 |
Turn in the following
Your graph showing the data plotted (should be curved)
Problem 2::A new truck costs $32000. The truck's value depreciates over time,which means it loses value.For tax purposes depreciation is calculated linearly. So V (current value) is equal to the P (original price) - n (years) times x (depreciation value). V = P - nx....If the truck is worth $24,500 after three years, find the depreciation value constant x. Now use that to write a formula write a general formula for the value (V) after n years. Your equation will only have n and V as variables. Using that formula find the value of this truck after 10 years. Find the age of the truck when the value is $0.
Turn in the following
value of X (depreciation constant)
general formula with V and n as variables
value of truck after 10 years
age of the truck when its value is zero.
Turn in typed by an attachment by the due date in the class schedule.
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Problem 1
Graph showing exponential increase in number of startbucks stores
Problem 2
Given :
Price of New truck P = 32,000
Price after 3 years V = 24,500
Using Equation:
V = P – nx
24500 = 32000 – 3x
3x = 7500
x = 2500
Therefore, the value of the depreciation constant is 2500
Equation => V = 32000 – 2500n
a) Value of truck after 10 years
Using this equation to calculate the value of the truck after 10 years (i.e. n = 10)
V = 32000 – 2500 * (10)
V = 7000
Value of truck after 10 years is $7,000
b) Age of the truck when value is $0
Using this equation to calculate n when V = 0
0 = 32000 – 2500n
n = 12.8
Value of the truck is $0 after 12.8 years
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