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Population Growth and Value Decline Mini-projects are designed to critically stretch your thinking, let you explore...

Population Growth and Value Decline

Mini-projects are designed to critically stretch your thinking, let you explore the concept, or make you look at a specific situation or related problem. By nature, they are more difficult than the regular exercises.

Problem:: The number of Starbucks stores grew after they first opened. The number of stores from 1990-2011, as reported on their corporate website is shown in the chart below..

Carefully plot the data. You should be able to see that the data is NOT linear, but actually exponential.

Year

Number of Starbucks stores

Year

Number of Starbucks stores

1990

84

2001

4709

1991

116

2002

5886

1992

165

2003

7225

1993

272

2004

8569

1994

425

2005

10241

1995

677

2006

12440

1996

1015

2007

15011

1997

1412

2008

16680

1998

1886

2009

16635

1999

2498

2010

16858

2000

3501

2011

17003

Turn in the following

Your graph showing the data plotted (should be curved)

Problem 2::A new truck costs $32000. The truck's value depreciates over time,which means it loses value.For tax purposes depreciation is calculated linearly. So V (current value) is equal to the P (original price) - n (years) times x (depreciation value). V = P - nx....If the truck is worth $24,500 after three years, find the depreciation value constant x. Now use that to write a formula write a general formula for the value (V) after n years. Your equation will only have n and V as variables. Using that formula find the value of this truck after 10 years. Find the age of the truck when the value is $0.

Turn in the following

value of X (depreciation constant)

general formula with V and n as variables

value of truck after 10 years

age of the truck when its value is zero.

Turn in typed by an attachment by the due date in the class schedule.

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Homework Answers

Answer #1

Problem 1

Graph showing exponential increase in number of startbucks stores

Problem 2

Given :

Price of New truck P = 32,000

Price after 3 years V = 24,500

Using Equation:

V = P – nx

24500 = 32000 – 3x

3x = 7500

x = 2500

Therefore, the value of the depreciation constant is 2500

Equation => V = 32000 – 2500n

a) Value of truck after 10 years

Using this equation to calculate the value of the truck after 10 years (i.e. n = 10)

 V = 32000 – 2500 * (10)

 V = 7000

Value of truck after 10 years is $7,000

b) Age of the truck when value is $0

Using this equation to calculate n when V = 0

 0 = 32000 – 2500n

 n = 12.8

Value of the truck is $0 after 12.8 years

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