Question

The mean income per person in the United States is $37,500, and the distribution of incomes...

The mean income per person in the United States is $37,500, and the distribution of incomes follows a normal distribution. A random sample of 12 residents of Wilmington, Delaware, had a mean of $46,500 with a standard deviation of $9,000. At the 0.010 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average?

  1. State the null hypothesis and the alternate hypothesis.
  1. State the decision rule for 0.010 significance level. (Round your answer to 3 decimal places.)
  1. Compute the value of the test statistic. (Round your answer to 2 decimal places.)
  1. Is there enough evidence to substantiate that residents of Wilmington, Delaware, have more income than the national average at the 0.010 significance level?
Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

ANSWER:

(OR) TRY THIS FOR TEST STATISTICS

NOTE:: I HOPE THIS ANSWER IS HELPFUL TO YOU......**PLEASE SUPPORT ME WITH YOUR RATING......

**PLEASE GIVE ME "LIKE".....ITS VERY IMPORTANT  FOR,ME......PLEASE SUPPORT ME .......THANK YOU

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The mean income per person in the United States is $37,500, and the distribution of incomes...
The mean income per person in the United States is $37,500, and the distribution of incomes follows a normal distribution. A random sample of 12 residents of Wilmington, Delaware, had a mean of $46,500 with a standard deviation of $9000. At the .010 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? (a) State the null hypothesis and the alternate hypothesis. H0: u is less than or equal...
The mean income per person in the United States is $39,500, and the distribution of incomes...
The mean income per person in the United States is $39,500, and the distribution of incomes follows a normal distribution. A random sample of 16 residents of Wilmington, Delaware, had a mean of $45,500 with a standard deviation of $9,800. At the 0.010 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? State the null hypothesis and the alternate hypothesis. State the decision rule for 0.010 significance level....
The mean income per person in the United States is $45,000, and the distribution of incomes...
The mean income per person in the United States is $45,000, and the distribution of incomes follows a normal distribution. A random sample of 17 residents of Wilmington, Delaware, had a mean of $55,000 with a standard deviation of $8,500. At the 0.100 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? State the null hypothesis and the alternate hypothesis. State the decision rule for 0.100 significance level....
The mean income per person in the United States is $37,000, and the distribution of incomes...
The mean income per person in the United States is $37,000, and the distribution of incomes follows a normal distribution. A random sample of 11 residents of Wilmington, Delaware, had a mean of $43,000 with a standard deviation of $8,800. At the 0.025 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? State the null hypothesis and the alternate hypothesis. State the decision rule for 0.025 significance level....
The mean income per person in the United States is $38,000, and the distribution of incomes...
The mean income per person in the United States is $38,000, and the distribution of incomes follows a normal distribution. A random sample of 13 residents of Wilmington, Delaware, had a mean of $48,000 with a standard deviation of $9,200. At the 0.100 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? State the null hypothesis and the alternate hypothesis. State the decision rule for 0.100 significance level....
A United Nations report shows the mean family income for Mexican migrants to the United States...
A United Nations report shows the mean family income for Mexican migrants to the United States is $26,450 per year. A FLOC (Farm Labor Organizing Committee) evaluation of 23 Mexican family units reveals a mean to be $37,190 with a sample standard deviation of $10,700. Does this information disagree with the United Nations report? Apply the 0.01 significance level. a. State the null hypothesis and the alternate hypothesis.   H0: μ =      H1: μ ≠    b. State the decision...
The cost of weddings in the United States has skyrocketed in recent years. As a result,...
The cost of weddings in the United States has skyrocketed in recent years. As a result, many couples are opting to have their weddings in the Caribbean. A Caribbean vacation resort recently advertised in Bride Magazine that the cost of a Caribbean wedding was less than $10,000. Listed below is a total cost in $000 for a sample of 8 Caribbean weddings. At the 0.010 significance level is it reasonable to conclude the mean wedding cost is less than $10,000...
A personnel director in a particular state claims that the mean annual income is greater in...
A personnel director in a particular state claims that the mean annual income is greater in one of the​ state's counties​ (county A) than it is in another county​ (county B). In County​ A, a random sample of 13 residents has a mean annual income of $42,000 and a standard deviation of $8800. In County​ B, a random sample of 11 residents has a mean annual income of $37,700 and a standard deviation of $5700. At At alphaαequals= 0.025 answer...
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and...
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and a population standard deviation of $3,500. The ship building association wishes to find out whether their welders earn more or less than $75,000 annually. The alternate hypothesis is that the mean is not $75,000. If the level of significance is 0.01, what is the critical value?
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and...
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and a population standard deviation of $3,500. The ship building association wishes to find out whether their welders earn more or less than $75,000 annually. The alternate hypothesis is that the mean is not $75,000. If the level of significance is 0.01, what is the critical value? ±2.576 −2.576 ±1.645 +1.645
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT