Business Weekly conducted a survey of graduates from 30 top MBA
programs. On the basis of the survey, assume the mean annual salary
for graduates 10 years after graduation is 124000 dollars. Assume
the standard deviation is 37000 dollars. Suppose you take a simple
random sample of 74 graduates.
Find the probability that a single randomly selected salary is more
than 123000 dollars.
P(X > 123000) =
Find the probability that a sample of size n=74n=74 is randomly
selected with a mean that is more than 123000 dollars.
P(M > 123000) =
Enter your answers as numbers accurate to 4 decimal places.
Hello Sir/ Mam
Given that:
Mean = | 124000.00 |
Standard Deviation = | 37000.00 |
(i)
(ii)
Updated details
Mean = 124000
S.D. = 37000/(74^0.5) = 4301.1626
I hope this solves your doubt.
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