Question

For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

In a survey of 1000 large corporations, 244 said that, given a choice between a job candidate who smokes and an equally qualified nonsmoker, the nonsmoker would get the job.

(a) Let p represent the proportion of all corporations preferring a nonsmoking candidate. Find a point estimate for p. (Round your answer to four decimal places.)

(b) Find a 0.95 confidence interval for p.

Lower Limit:

Upper Limit:

(c) As a news writer, how would you report the survey results regarding the proportion of corporations that would hire the equally qualified nonsmoker?

(d) What is the margin of error based on a 95% confidence interval?

Answer 1

Here it is given that in a survey of 1000 large corporations, 244 said that, given a choice between a job candidate who smokes and an equally qualified nonsmoker, the nonsmoker would get the job.

a. Hence point estimate of p is

b. For 95% CI, z value is 1.96 as P(-1.96<z<1.96)=0.95

So Margin of Error is

Hence CI is

c. A survey of 1000 large corporations has shown that 24.4% would intentionally hire a non-smoker over an equally qualified smoker.

d. Margin of Error is

Lower Limit: 0.214

Upper Limit: 0.274

c.