Question
Assume that 30.3% of people have sleepwalked. Assume that in a random sample of 1549 adults,...
Assume that 30.3% of people have sleepwalked. Assume that in a random sample of 1549 adults, 509 have sleepwalked.
a. Assuming that the rate of 30.3% is correct, find the probability that 509 or more of the 1549 adults have sleepwalked.
b. Is that result of 509 or more significantly high?
c. What does the result suggest about the rate of 30.3%?
Homework Answers
Answer #1
Given
sample size = n = 1549
x = 509
a)
sample proportion 
= x / n= 509 /1549 = 0.3286
p = 30.3% = 0.303
Z = 2.19
P(Z > 2.19) = 0.01426
b)
consider at 
= 0.05
P-value <
Yes , it is significantly high
c)
It suggest that true percentage of people who sleep walked is greater than 30.3%
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