A marketing firm gathered the following data on popup ads received in an hour of screen time on I-phones and Samsung phones for 12 individuals to determine if there is a difference in the number of ads received.
Number of ads |
Type of phone |
20 |
I-phone |
25 |
Samsung |
15 |
I-phone |
30 |
Samsung |
35 |
Samsung |
25 |
I-phone |
40 |
Samsung |
10 |
I-phone |
30 |
Samsung |
35 |
I-phone |
20 |
Samsung |
15 |
I-phone |
a. Independent variable=Type of phone; Dependent variable=An hour of screen time
b.
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
I-phone | 6 | 120 | 20 | 80 | ||
Samsung | 6 | 180 | 30 | 50 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 300 | 1 | 300 | 4.615385 | 0.057224 | 4.964603 |
Within Groups | 650 | 10 | 65 | |||
Total | 950 | 11 |
SST=950, SSunacct=650, and SSacct=300.
c. eta square=SSacct/SST=300/950=0.3158 i.e. 31.58% of total variation in hour of screen time is explained by type of phone.
d. Standard deviation for I-phone=8.9443; Standard deviation for Samsung=7.0711.
e.
f. Since p-value=0.057224>0.05, there is insignificant difference in the number of ads received.
Get Answers For Free
Most questions answered within 1 hours.