There is a large supply of light bulbs with the average life of 1000 hours and the standard deviation of 50 hours.
Using Ti-34 calculator
Equations/answer written out using
binomcdf(x,x,x)
Binompdf(x,x,x)
Invnorm
InvT
tcdf
If possible/needed to solve the equation
Solution:-
a) When a light bulb is drawn at random, the probability that it will last more than 1020 hours is 0.3446.
x = 1020
By applying normal distribution:-
z = 0.40
Use the z-score table or p-value calculator.
P(z > 0.40) = 0.3446
normalcdf(1020, 1099, 1000,50) = 0.3446
b) When a random sample of 25 light bulbs is drawn. The probability that the sample average life is more than 1020 hours is 0.0228.
x = 1020
By applying normal distribution:-
z = 2.0
Use the z-score table or p-value calculator.
P(z > 2.0) = 0.0228
normalcdf(1020, 1099, 1000,10) = 0.0228
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