Question

We have a group of families whose annual incomes are normally distributed with a mean of...

We have a group of families whose annual incomes are normally distributed with a mean of $45,000 and a standard deviation of $11,000. What percentage of these families has an annual income between $29,600 and $53,800?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Solution:

Given the income is normally distributed

Mean = 45,000

Standard deviation = 11,000

We have to find P(29,600< x < 53800)

Since it is normally distributed , from z table

So, There are 70.73% of families has an annual income between $29,600 and $ 53,800 .

If this answer helps you please upvote this.

Thank you.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The weekly incomes of a large group of middle managers are normally distributed with a mean...
The weekly incomes of a large group of middle managers are normally distributed with a mean of $1,800 and a standard deviation of $200. Use the normal distribution to calculate the following: A. What percent of income lies within $400 of the population mean? B. 68% of observations lie within which two values?
#5 A study of adult cell phone owners found that their annual income was normally distributed...
#5 A study of adult cell phone owners found that their annual income was normally distributed with a mean of $41,200 and a standard deviation of $18500. If sellers of cell phones wish to target the adult owners of cell phones whose incomes are in the top 83%. What is the minimum income level for the top 83% of the group? #4 The heights of high-school students are normally distributed with a mean of μ = 62.5 inches and standard...
A new tax law is expected to benefit “middle income” families, those with incomes between $25,000...
A new tax law is expected to benefit “middle income” families, those with incomes between $25,000 and $35,000. If family income is normally distributed with mean $25,000 and standard deviation $6,000, what percentage of the population will benefit from the law? Round your answer to two decimal places.
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and...
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and a population standard deviation of $3,500. The ship building association wishes to find out whether their welders earn more or less than $75,000 annually. The alternate hypothesis is that the mean is not $75,000. If the level of significance is 0.01, what is the critical value?
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and...
The mean annual incomes of certified welders are normally distributed with the mean of $75,000 and a population standard deviation of $3,500. The ship building association wishes to find out whether their welders earn more or less than $75,000 annually. The alternate hypothesis is that the mean is not $75,000. If the level of significance is 0.01, what is the critical value? ±2.576 −2.576 ±1.645 +1.645
The median annual income for families living in the United States is 56200 . Annual incomes...
The median annual income for families living in the United States is 56200 . Annual incomes in thousands of dollars for a sample of 50 families living in Chicago, Illinois, are shown. Use the sample data to see if it can be concluded that the families living in Chicago have a median annual income greater than 56200 . Use alpha .05 . What is your conclusion? 103.9 37.0 62.1 75.7 91.8 45.8 86.8 64.1 59.7 54.8 62.4 49.5 110.2 43.6...
Suppose the household incomes for Kamloops are normally distributed with mean $62,000 and standard deviation $6,800....
Suppose the household incomes for Kamloops are normally distributed with mean $62,000 and standard deviation $6,800. a) If 50 households are randomly selected, find the probability that their mean household income is below $64,000. b) If households with the bottom 20% of incomes qualify for a special tax cut, what is the maximum income required to qualify for the tax cut?
a. The annual salaries of employees in a large company are approximately normally distributed with a...
a. The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $2000. What proportion of employees earned between $45,000 to $55,000? (3 decimal places) b. The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $2000. What is the probability of randomly selecting one employee who earned between $45,000 to $55,000? (3 decimal places)
1 The weight of cans of fruit is normally distributed with a mean of 1,000 grams...
1 The weight of cans of fruit is normally distributed with a mean of 1,000 grams and a standard deviation of 25 grams. What percent of the cans weigh 1075 grams or more? 1B. What percentage weighs between 925 and 1075 grams? 2. The weekly mean income of a group of executives is $1000 and the standard deviation of this group is $75. The distribution is normal. What percent of the executives have an income of $925 or less? 2B....
1. The annual income of single individuals in Canada is normally distributed with mean $45,000 and...
1. The annual income of single individuals in Canada is normally distributed with mean $45,000 and standard deviation $10,000. a. [1] What is the z-score of an annual income of $60,000? b. [2] What proportion of people have an annual income of at least $60,000?Illustrate your calculations. Annual Income Standard Normal Distribution Fear not, for I am with you; be not dismayed, for I am your God; I will strengthen you, I will help you, I will uphold you with...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT