Question

Given the following sample data:

8 9 10 12 8 9 13 9 10 12

1) Find the: [2, 2, 1 points]

a. Mean x

b. Median

c. Mode

2) Find the variance s2and standard deviation s [4 points]

3) What percent of this sample data is between x − 2s and x + 2s? [1 point]

Answer 1

Data values (arranged) = 8, 8, 9, 9, 9, 10, 10, 12, 12, 13

a) Mean = Sum/(number of terms) = 100/10 = 10

10 is the mean.

b) Median = Average of 5th and 6th term = (9 +10)/2 = 9.5

9.5 is the median.

c) Mode = 9 (because that's the most repeating term)

2)

(approx).

Standard deviation = (approx)

3) x - 2s = 10-2*1.764 = 6.472

x + 2 s = 10+2*1.764 = 13.528

As all data lies between 6.472 and 13.528 hence 100% of this sample data is between x - 2s and x + 2s.