Mean = 68 inches
Standard deviation = 0.44 inches
We need to find the longest 5%
let x be the length
P[ X > x ] = 5%
P[ X > x ] = 0.05
P[ ( X - mean )/ Standard deviation > ( x - mean )/ Standard deviation ] = 0.05
P[ ( X - 68 )/ 0.44 > ( x - 68 )/ 0.44 ] = 0.05
P[ Z > ( x - 68 )/ 0.44 ] = 0.05
Also,
P[ Z > 1.645 ] = 0.05
Comparing
( x - 68 )/ 0.44 = 1.645
x - 68 = 0.44*1.645
x - 68 = 0.7238
x = 68 + 0.7238
x = 68.7238
x = 68.72 inches
P[ X > 68.72 ] = 5%
E. 68.72 inches
Get Answers For Free
Most questions answered within 1 hours.